Chemistry 112

The Table of Standard Reduction Potentials gives a reduction potential of 0.771 V for the reduction of Fe3+(aq) to Fe2+(aq) under standard acidic conditions. What is the reduction potential under standard basic conditions?

There appears to be no explicit pH dependence in the reduction under standard acidic conditions:

Fe3+(aq) + e → Fe2+(aq)

However, this does not take into account all of the reactivity under basic conditions. Under standard basic conditions (1.00 M OH, pH = 14.00) both iron cations will precipitate as hydroxide salts:

Fe(OH)3(s) + e → Fe(OH)2(s) + OH(aq)

Thus, the contribution of the precipitation chemistry must also be accounted for in determining the reduction potential.

Fe3+(aq) + e → Fe2+(aq) red = 0.771 V ΔG° = –nFE° = –(1)(96485)(0.771) = –74400 J

Fe(OH)3(s) Fe3+(aq) + 3 OH(aq) Ksp = 4×10–38 ΔG° = –RTlnKeq = –(8.314)(298)ln(4×10–38) = +213000 J

Fe2+(aq) + 2 OH(aq) Fe(OH)2(s) Keq = 1/Ksp = 1/8.0×10–16 = 1.3×1015 ΔG° = –RTlnKeq = –(8.314)(298)ln(1.3×1015) = –86200 J

Add the three reactions together to give the net reaction:

Fe(OH)3(s) + e → Fe(OH)2(s) + OH(aq)

ΔG° = –74400 + 213000 –86200 = 52000 J

E° = –ΔG°/nF = –(52000)/(1)(96485) = –0.54 V