Complete and balance:
Cr2O72–(aq) + SO2(g)
→ Cr(OH)3(s) + SO42–(aq)
This reaction must be done in base. This is indicated by the presence of the chromium(III)
hydroxide product (a weak base).
Oxidation half–reaction (S goes from +4 to +6):
SO2(g) →
SO42–(aq)
S is mass balanced
Back
Next
