Chemistry 112

Buffer plus strong acid:

First change the mass to moles: 1.0 g HBr × 1 mol HBr/(1.0 g + 79.9 g) = 0.012 mol in 1.00 L

[HBr] = 0.012 M

(The pH of this strong acid in the absence of buffer would be pH = –log(0.012) = 1.92)

NaNO₂(aq) → Na⁺(aq) + NO₂^–(aq)

HNO₂(aq) + H₂O(l) → ← H₃O⁺(aq) + NO₂^–(aq)

 

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