NH3(aq) + H2O(l) → ← NH4+(aq) + OH–(aq)
Kb = [NH4+]e[OH–]e [NH3]e
Ka (NH4+) = 5.6×10–10
Kb (NH3) = Kw/Ka = 1.0×10–14/5.6×10–10 = 1.8×10–5
Initial0.10 0 0
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