Lead Chloride:
PbCl2(s) → ← Pb2+(aq) + 2 Cl–(aq)
Ksp = [Pb2+]e[Cl–]e2 = 1.6×10–5
Initial00
Change+x+2x
Equilibriumx2x
1.6×10–5 = [x][2x]2 = 4x3
x = 1.6×10–2
The solubility of lead chloride = 1.6×10–2 M
Return
