For the base:
B(aq) + H2O(l) → ← HB+(aq) + OH–(aq) Kb(B)
For the conjugate acid
HB+(aq) + H2O(l) → ← H3O+(aq) + B(aq) Ka(HB+)
If we add these two reactions together:
2 H2O(l) → ← H3O+(aq) + OH–(aq)
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