The hydrogen ion transfer is onto the ammonia, giving ammonium ion as the product. The other product is cyanide ion.
HCN(aq) + NH3(aq) ? NH4+(aq) + CN–(aq)
We need to find Ka values using the Table of Acid Ionization Constants
Ka(acid) = 6.2×10–10
Ka(conjugate acid) = 5.6×10–10
Kc = Ka(acid)/Ka(conjugate acid) = (6.2×10–10)/(5.6×10–10) = 1.1 < 100