H3PO4(aq) + H2O(l) → ← H3O+(aq) + H2PO4–(aq)
Ka1 = [H3O+]e[H2PO4–]e [H3PO4]e = 7.1×10–3
Initial0.037 0 0
Change–x +x +x
Equilibrium0.037 – x x x
Can we approximate? 0.037/0.0071 = 5.2 NO!
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