Chemistry 112

Barium sulfate:

BaSO4(s) Ba2+(aq) + SO42–(aq)

Ksp = [Ba2+]e[SO42–]e = 1.1×10–10


Initial00

Change+x+x

Equilibriumxx

1.1×10–10 = [x][x] = x2

x = 1.0×10–5

The solubility of barium sulfate = 1.0×10–5 M

 

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