Consider the reaction:
C5H5Rh(CO)2(sol) + L(sol) → C5H5Rh(CO)L(sol) + CO(sol)
The following data sets were measured experimentally:
(0) L = P(C4H9)3
Experiment # [C5H5Rh(CO)2] (M) [L] (M) Initial Rate (Ms–1)
1 0.0040 0.053 7.0×10–3
2 0.0080 0.053 1.4×10–2
3 0.0080 0.027 7.0×10–3
(1) L = P(OC4H9)3
Experiment # [C5H5Rh(CO)2] (M) [L] (M) Initial Rate (Ms–1)
1 0.0012 0.660 3.0×10–3
2 0.0024 0.660 6.0×10–3
3 0.0024 0.330 3.0×10–3
(2) L = P(C4H9)3
Experiment # [C5H5Rh(CO)2] (M) [L] (M) Initial Rate (Ms–1)
1 0.0020 0.053 3.5×10–3
2 0.0010 0.053 1.7×10–3
3 0.0010 0.027 8.5×10–4
(3) L = P(OC4H9)3
Experiment # [C5H5Rh(CO)2] (M) [L] (M) Initial Rate (Ms–1)
1 0.00060 0.660 1.5×10–3
2 0.00030 0.660 7.5×10–4
3 0.00030 0.330 3.7×10–4
(4) L = P(C4H9)3
Experiment # [C5H5Rh(CO)2] (M) [L] (M) Initial Rate (Ms–1)
1 0.0080 0.053 1.4×10–2
2 0.016 0.053 2.8×10–2
3 0.016 0.027 1.4×10–2
(5) L = P(OC4H9)3
Experiment # [C5H5Rh(CO)2] (M) [L] (M) Initial Rate (Ms–1)
1 0.0024 0.660 6.0×10–3
2 0.0048 0.660 1.2×10–2
3 0.0048 0.330 6.0×10–3
(6) L = P(C4H9)3
Experiment # [C5H5Rh(CO)2] (M) [L] (M) Initial Rate (Ms–1)
1 0.0040 0.027 3.5×10–3
2 0.0080 0.027 7.0×10–3
3 0.0080 0.014 3.5×10–3
(7) L = P(OC4H9)3
Experiment # [C5H5Rh(CO)2] (M) [L] (M) Initial Rate (Ms–1)
1 0.0012 0.220 1.0×10–3
2 0.0024 0.220 2.0×10–3
3 0.0024 0.110 1.0×10–3
(8) L = P(C4H9)3
Experiment # [C5H5Rh(CO)2] (M) [L] (M) Initial Rate (Ms–1)
1 0.0040 0.018 2.3×10–3
2 0.0080 0.018 4.7×10–3
3 0.0080 0.0090 2.4×10–3
(9) L = P(OC4H9)3
Experiment # [C5H5Rh(CO)2] (M) [L] (M) Initial Rate (Ms–1)
1 0.0024 0.330 3.0×10–3
2 0.0048 0.330 6.0×10–3
3 0.0048 0.170 3.0×10–3
Turn in the following:
Name
Student ID Number
For the data set that corresponds to the last digit of your student ID number, find the rate law and the value of the rate constant, including units. Show your work.