Use the buffer described in Homework 17 and find the pH if a) 1.0 g of HCl(g) is added to 1.0 L of the solution and b) 1.0 g of NaOH(s) is added to 1.0 L of the solution.
A typical equilibrium problem: write the relevant reactions, write the mass action expression, set up an ICE table, and then solve for the unknown.
Let [NH3]init = Cam = 4th5th/100 and [NH4Cl]init = 1st2nd/100 = 0.10 M for all students
NH4+(aq) + Cl–(aq) ← NH4Cl(aq)
NH4+(aq) + H2O(l) → ← H3O+(aq) + NH3(aq)
Ka = [H3O+]e[NH3]e [NH4+]e = 5.6×10–10
Initial0.10 0 Cam
Change– x +x – x
Initial0.10 – x x Cam + x
Approximate? 0.10/5.6×10–10 = 1.8×108 > 100, Yes
5.6×10–10 = (x)(Cam)/(0.10)
x = [H3O+]e = (5.6×10–10)(0.10)/(Cam)
pH = –log[H3O+]e, all to two places past the decimal.
a) Add 1.0 g of HCl(g) so the concentration of HCl is 1 mol/(1.0 g + 35.5 g)(1.0 L) = 0.027 M
NH4+(aq) + Cl–(aq) ← NH4Cl(aq)
NH4+(aq) + H2O(l) → ← H3O+(aq) + NH3(aq)
A/B reaction:NH4+(aq) + Cl–(aq) ← HCl(aq) + NH3(aq)
Ka = [H3O+]e[NH3]e [NH4+]e = 5.6×10–10
Initial0.10 0 Cam
A/B reaction+0.027 0 – 0.027
Change– x +x – x
Equilibrium0.127 – x x Cam – 0.027 + x
Approximate? 0.10/5.6×10–10 = 1.8×108 > 100, Yes
5.6×10–10 = (x)(Cam – 0.027)/(0.127)
x = [H3O+]e = (5.6×10–10)(0.10)/(Cam)
pH = –log[H3O+]e, all to two places past the decimal.
b) Add 1.0 g of NaOH(s) so the concentration of NaOH is 1 mol/(23.0 g + 16.0 g + 1.0 g)(1.0 L) = 0.025 M
NH4+(aq) + Cl–(aq) ← NH4Cl(aq)
NH4+(aq) + H2O(l) → ← H3O+(aq) + NH3(aq)
A/B reaction:NH4+(aq) + NaOH(s) → Na+(aq) + NH3(aq) + H2O(l)
Ka = [H3O+]e[NH3]e [NH4+]e = 5.6×10–10
Initial0.10 0 Cam
A/B reaction– 0.025 0 + 0.025
Change– x +x – x
Equilibrium0.075 – x x Cam – 0.025 + x
Approximate? 0.10/5.6×10–10 = 1.8×108 > 100, Yes
5.6×10–10 = (x)(Cam – 0.025)/(0.075)
x = [H3O+]e = (5.6×10–10)(0.10)/(Cam)
pH = –log[H3O+]e, all to two places past the decimal.
[NH3]init (M) [NH4Cl]init (M) pH pH after HCl pH after NaOH
0.50 0.10 9.95 9.82 10.10
0.52 0.10 9.97 9.84 10.11
0.54 0.10 9.98 9.86 10.13
0.55 0.10 9.99 9.87 10.14
0.56 0.10 10.00 9.87 10.14
0.57 0.10 10.01 9.88 10.15
0.58 0.10 10.02 9.89 10.16
0.59 0.10 10.02 9.90 10.17
0.60 0.10 10.03 9.91 10.17
0.61 0.10 10.04 9.91 10.18
0.62 0.10 10.04 9.92 10.19
0.63 0.10 10.05 9.93 10.19
0.65 0.10 10.06 9.94 10.21